FS#46213 - [systemd] Don't use $pkgname in paths in split packages
Attached to Project:
Arch Linux
Opened by Que Quotion (quequotion) - Sunday, 06 September 2015, 11:29 GMT
Last edited by Dave Reisner (falconindy) - Sunday, 06 September 2015, 18:20 GMT
Opened by Que Quotion (quequotion) - Sunday, 06 September 2015, 11:29 GMT
Last edited by Dave Reisner (falconindy) - Sunday, 06 September 2015, 18:20 GMT
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Details
Description: systemd's pkgbuild is a split package that uses
$pkgname to refer to the directory where the source is
extracted. Build fails when building one of the other
packages with "makepkg --pkg targetpkg" because makepkg will
use the given package name for $pkgname, but the directory
is always "systemd".
Rather, as a split package this one should have a "pkgbase" variable defined and use $pkgbase in non-split functions like prepare() and build(). Additional info: * package version(s) * config and/or log files etc. Details in this forum thread: https://bbs.archlinux.org/viewtopic.php?pid=1559685 Steps to reproduce: 1. Download the systemd package source files 2. Make one of the split packages (makepkg --pkg libsystemd) |
This task depends upon
Closed by Dave Reisner (falconindy)
Sunday, 06 September 2015, 18:20 GMT
Reason for closing: Fixed
Additional comments about closing: Fixed in SVN, will not be release until systemd 226.
Sunday, 06 September 2015, 18:20 GMT
Reason for closing: Fixed
Additional comments about closing: Fixed in SVN, will not be release until systemd 226.
I'm happy to fix this, but it seems like a bug in makepkg that the value of 'pkgname' varies depending on the options passed to makepkg. Specifically this:
https://projects.archlinux.org/pacman.git/tree/scripts/makepkg.sh.in#n2067
Is a convenient, but really poor hack.
edit: then again, it's also probably poor form to refer to $pkgname at all when it's declared as an array...