Arch Linux

Summary and Info:

Why does `pacman -Qdqt` exit with status 1 whether it finds anything or not? I would expect it to exit with status 1 if it found anything, 0 otherwise, although I could see the other implementation making sense as well (since arguably it is a search algorithm and finding nothing is an error). However, returning 1 in both cases makes no sense to me.

As an additional benefit, if this returned distinct codes, the following convenient action would be possible:

pacman -Qdqt && pacman -Qdqt | pacman -Rns -

or

pacman -Qdqt || pacman -Qdqt | pacman -Rns -

Both of these are more convenient at the command line and more readable in Bash scripts than the if...fi construct required to achieve the same effect now.

Steps to Reproduce:

With unneeded packages:
$ yaourt -Qdqt
gendesk
lib32-libao
lib32-sdl
nasm
subversion
$ echo $?
1

Without:
$ yaourt -Qdqt
$ echo $?
1