Description:

I get an issue on gcc's compilation.
I used mistakenly memcpy with memset's prototype.

compilation's line:
gcc -I ./include -I ../commun_/include -g -O0 -c -o source/client/client_send.o source/client/client_send.c

error message:
source/client/client_send.c:21:9: internal compiler error: in ix86_copy_addr_to_reg, at config/i386/i386.c:21722
memcpy(&buff, 0, sizeof(buff));
^
code:
int client_send(t_client *self)
{
t_buff buff;

memcpy(&buff, 0, sizeof(buff));
if (write(self->fd, &buff, sizeof(buff)) == -1)
return (int_perror("write"));
return (SUCCESS);
}

Additional info:
gcc (GCC) 4.8.2 20140206 (prerelease)
default config